2^m+^1=16^m+7

Simple and best practice solution for 2^m+^1=16^m+7 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 2^m+^1=16^m+7 equation: 



2^m+^1=16^m+7

We move all terms to the left:

2^m+^1-(16^m+7)=0

We add all the numbers together, and all the variables

2^m-(16^m+7)=0

We get rid of parentheses

2^m-16^m-7=0

We move all terms containing m to the left, all other terms to the right

2^m-16^m=7

See similar equations:

| 2z+8=4z-3 | | 6=3b^2 | | 8w+9=4w+29 | | x+2/3=45 | | 3r+1=≤1 | | 5x3=17 | | 8y+4=3y-49 | | (x-5)²-10(x-5)=24 | | 4x+4=8x+27 | | 2n+5=10-3n | | (x-3)²-4(x-3)=5 | | 12-5v=2v+5 | | (1.89)=3^x | | 2z+4=3z-15 | | 225=3x3x5x5 | | 9(k-4)=4·3 | | Y=-8/9x-7 | | 1-3x^2=-5x | | 3x+0.4=9.4 | | 2y+5=3y-14 | | H(t)=-16t²+32t+4 | | 5+c=-15 | | 1x-16=-3 | | 1/4x=7/2x-3 | | −5+3x=−5x= | | -7+22=2x-14 | | -x^2x+6x-8=3x+7 | | 6(2x+5)=2(5x-3) | | y+5y+2y=0 | | 7x-15=9x+5 | | (5y-9)+96=180 | | 2(3^x)=16 |

Equations solver categories